Question

найдите область определения функции
________
y= √ 12-4x-x^2
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1-x

Answer 1

1) 12 - 4x - x² ≥ 0                                    2) 1 - x ≠ 0
x² + 4x - 12 ≤ 0                                             x ≠ 1
(x + 6)(x - 2) ≤ 0

   +                  --                    +
____________₀____________
       - 6             1             2 
x ∈ [- 6 ; 1)∪(1 ; 2]