Question

Найти нули функции
y=2x^2+6x+4
y=6x^2+4x

Answer 1

$1. \ y=2x^2+6x+4 \ 2x^2+6x+4=0 \ x^2+3x+2=0 \ D=3^2-4*2=9-8=1 \ x= (-3б sqrt{1)} :2 \ x_{1} =-2;x_2=-1\ \ 2. \ y=6x^2+4x \ 6x^2+4x=0 \ 3x^2+2x=0 \ x(3x+2)=0 \ x_1=0; \ 3x_2+2=0 \ 3x_2=-2 \ x_2=-2/3$