Question

$(8x + 1) times (2x - 3) - (4x - 2) ^{2} = 1$
Решите уравнение

Answer 1

(8x+1)*(2x-3)-(4x-2)²=1
16x²-24x+2x-3-(16x²-16x+4)=1
16x²-24x+2x-3-16x²+16x-4=1
-6x-7=1
-6x=1+7
-6x=8
x=- 4/3

Answer 2

спасибо)