Question

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$lim_{x to 0}frac{e^{x}e^{-x}-2}{x^2}$

Answer 1

$lim_{x to 0}frac{e^{x}e^{-x}-2}{x^2}=lim_{x to 0}frac{1-2}{x^2}=lim_{x to 0}frac{-1}{x^2}={infty}$