Question

решите уровнение 12/1+|х|=3

Answer 1

$displaystyle frac{12}{1+|x|} =3 \ \ frac{12}{1+|x|} = frac{3}{1} \ \ \ 1*12=3(1+|x|) \ \ 12 =3(1+|x|) \ \ 4=1+|x| \ \ -|x|=1-4 \ \ -|x|=-3 \ \ |x|=3 \ \ x= pm 3$

Answer 2

другое дело