Question

5x^2>2x решите неравенство

Answer 1

$5x^2 textgreater 2x \ 5x^2-2x textgreater 0 \ x(5x-2) textgreater 0 \ left { {{x textgreater 0} atop {5x-2 textgreater 0}} right. left { {{x textgreater 0} atop {x textgreater frac{2}{5} }} right. \ left { {{x textless 0} atop {5x-2 textless 0}} right. left { {{x textless 0} atop {x textless frac{2}{5} }} right.$
x∈($frac{2}{5}$;+∞)
x∈(-∞;0)
x∈(-∞;0)∪(2/5;+∞)

Answer 2

сложно ахахах