Question

arcsin1-2arccos(-Корень из 2/2)
2arccos0.5-3arcsin- 1/2

Answer 1

$displaystylearcsin1-2arccosbigg(-frac{sqrt2}2bigg)=frac{pi}2-2*frac{3pi}4=frac{pi}2-frac{3pi}2=boxed{-pi}\\2arccosfrac{1}2-3arcsinbigg(-frac{1}2bigg)=2*frac{pi}3-3*bigg(-frac{pi}6bigg)=\\=frac{4pi}6+frac{3pi}6=boxed{frac{7pi}6}$