Question

2sin^x-sin-1=0 решите пж срочно

Answer 1

2sin²x-sinx-1=0
(sinx-1)(2sinx+1)=0
sinx=1
sinx=-1/2
х1=П/2+2Пn, n€Z
x2=-П/6+2Пk, k€Z
x3=-5П/6+2Пm, m€Z