Question

help me please
solve the system
x^3-y^3=19
x-y=1

Answer 1

(x-y)(x^2+xy+y^2)=19
x-y=1
x^2+xy+y^2=19
x=1+y
(1+y)^2+(1+y)y+y^2=19
1+2y+y^2+y+y^2+y^2-19=0
3y^2+3y-18=0
y^2+y-6=0
D=25
y1,2=(-1+-5)/6=2/3; -1
x1=1+2/3=5/3
x2=1-1=0