Question

6x*(2x^9)^4/(4x^12)^3 при х=5

Answer 1

$displaystyle frac{6x*(2x^9)^4}{(4x^{12})^3}=frac{6x*2^4x^{36}}{4^3x^{36}}=frac{6x*2^4}{2^6}=frac{6x}4,quad x=5\\frac{30}4=boxed{frac{15}2}}$