Question

Найти производную функции
f(x)=ln7x+8^4-5x

Answer 1

$f'(x) = (ln7x)' + (8 ^{4-5x})'= frac{1}{7x} *(7x)' + 8 ^{4-5x}ln8*(4-5x)'= frac{1}{7x}*7-$$5ln8*8 ^{4-5x} = frac{1}{x}- 5ln8*8 ^{4-5x}$