Question

Решите уравнение:

1) x^4 - 3x^2 + 2 = 0

2) x^4 - 9x^2 - 10 = 0

Answer 1

$x^4 - 3x^2 + 2 = 0 \ y^2 - 3y + 2 = 0 \ D=9-8=1 \ y_1=1 \ y_2=2 \ x_1=pm1 \ x_2=pm sqrt{2}$

$x^4 - 9x^2 -10 = 0 \ y^2 - 9y -10 = 0 \ D=81+40=121 \ y_1=10 \ y_2 neq -1<0 \ x=pm sqrt{10}$