Question

$frac{6x-5}{3x-1} - frac{x-2}{x+3} = 1$

Answer 1

(6x-5)(x+3)-(x-2)(3x-1)=(3x-1)(x+3)
6x^2+18x-5x-15-(3x^2-x-6x+2)=3x^2+9x-x-3
6x^2+13x-15-3x^2+7x-2=3x^2+8x-3
20x-17=8x-3
12x=14
x=14/12=7/6