Question

разложите на множители: xz^12+xh^12−hz^12−h^13

Answer 1

$xz^{12}+xh^{12}-hz^{12}-h^{13}=\ =(xz^{12}-hz^{12})+(xh^{12}-h^{13})= \ =z^{12}(x-h)+h^{12}(x-h)=\ =(x-h)(z^{12}+h^{12})=\ =(x-h)((z^4)^3+(h^{4})^3)=\ = (x-h)(z^4+h^4)(z^8-h^4z^4+h^8)$

Answer 2

xz¹²+xh¹²-hz¹²-h¹³.
xz¹²-hz¹²+xh¹²-h¹³.
z¹²(x-h)+h¹²(x-h).
(x-h)((z⁴)³+(h⁴)³).
(√x²-√h²)(z⁴+h⁴)(z^8-z⁴h⁴+h^8).
(√x+√h)(√x-√h)(z⁴+x⁴)(z^8-(zh)⁴+h^8).