Question

(2целых2/3х+1целая3/7х)*21=58

Answer 1

(2 целых2/3х + 1 целая 3/7х)*21=58
$frac{8}{3} x+ frac{10}{7} x= frac{56}{21} x + frac{30}{21} x= frac{86}{21} x= frac{86}{21} x * frac{21}{1} =86 x= \ 86 x^=58 \ x = frac{58}{86} \ x^{2}= frac{29}{43} = 0.6744$