Question

2)y=5x^2+9x-2
1)При x=- 1/5
2)Нули функций

Answer 1

$y=5x^2+9x-2 \ \ 1)x=-1/5 \ 5* frac{1}{25} -9* frac{1}{5}-2= frac{1}{5}- frac{9}{5}-2= frac{1-9-10}{5}= -frac{18}{5} =-3.6 \ \ 2)5x^2+9x-2=0 \ D=81+40=121=11^2 \ x_1=(-9-11)/10=-2 \ x_2=(-9+11)/10=1/5$