Question

Вычислите
sin(-11π/6)
sin7π/6
cos(-7π/3)

Answer 1

Sin (-11π/6 ) = 0,5
sin7π/6 = -0,5
Cos (-7π/3 ) = 0,5

Answer 2

$1)sin( - frac{11pi}{6} ) = - sin(pi + frac{5pi}{6} ) = sin frac{5pi}{6} = frac{1}{2}$
$2)sin frac{7pi}{6} = - sin(pi + frac{pi}{6} ) = sin frac{pi}{6} = frac{1}{2}$
$3)cos( - frac{7pi}{3} ) = - cos(2pi + frac{pi}{3} ) = cos frac{pi}{3} = frac{1}{2}$