Question

Sin(2pi-x)-cos(3pi/2+x)+1=0

Answer 1

sin(2π-x)-cos(3π/2+x)+1=0,
-sinx-sinx+1=0,
sinx=0.5,
x1=π/6+2πn, n∈Z,
x2=5π/6+2pk, k∈Z.