Question

Помогите кому не сложно

Answer 1

По скольку $D textgreater 0$, то $D= (sqrt{D})^2$

$(2ax+b)^2-( sqrt{D} )^2=0$

$(2ax+b-sqrt{D} )(2ax+b+sqrt{D} )=0$

$2ax+b-sqrt{D} =0 or 2ax+b+sqrt{D}=0$

$2ax=-b+sqrt{D} or 2ax=-b-sqrt{D}$

$2ax=-b+sqrt{D} or 2ax=-b-sqrt{D}$

$2ax=-bpmsqrt{D}$

случай 1:
$x=frac{-bpmsqrt{D}}{2a}, if a in (-infty; 0) cup (0; +infty) and bin(-infty; +infty)$

случай 2:
$0*x=-bpm sqrt{D}, if ain{0}$

под-случай 21:
$0*x=0, if b=pm sqrt{D}\ xin(-infty; +infty), if b=pm sqrt{D}$

под-случай 22:
$0*x=-bpm sqrt{D} neq 0 , if b neq pm sqrt{D}\ xnotin(-infty; +infty), if b neq pm sqrt{D}$