Question

Номер 14 сделайте пж

Answer 1

$frac{6}{(x-3)(x-1)} + frac{13-7x}{x-1} - frac{3}{x-3}=0$
$frac{6-13x+7 x^{2} +39-21x-3x+3}{(x-3)(x-1)} =0$
$frac{7 x^{2} -37x+48}{(x-3)(x-1)} =0$
7x² - 37x + 48 = 0         x ≠ 3 ,   x ≠ 1
D = ( -37)² - 4 * 7 * 48 = 1369 - 1344 = 25
$X _{1} = frac{37+ sqrt{25} }{14}= frac{37+5}{14}= frac{42}{14}=3$
$X _{2}= frac{37- sqrt{25} }{14}= frac{37-5}{14} = frac{32}{14}= 2frac{2}{7}$