Question

1)определить Mr(K3BO3).

2)Найдите долю каждого элемента в соединении Ca3(As03)2

Answer 1

1) Mr(K3BO3) = 3*39+11+3*16 = 176

2) Mr(Ca3(AsO3)2) = 3*40+2*75+6*16 = 366
W(Ca) = 120/366 = 0.33 = 33%
W(As) = 150/366 =0.41 = 41%
W(O) = 96/366 = 0.26 = 26%