Question

Разложите на множители (c-4)^2-3(4-c)^3

Answer 1

$(c-4)^2-3(4-c)^3=(c-4)^2-3((-1)*(c-4))^3=\= (c-4)^2-3*(-1)^3*(c-4)^3=\= (c-4)^2-3*(-1)*(c-4)*(c-4)^2=\= 1*(c-4)^2+3*(c-4)*(c-4)^2=\= (1+3(c-4))*(c-4)^2=(1+3c-12)*(c-4)^2=\= (3c-11)(c-4)^2$

Answer 2

Спасибо огромное!!!♡