Question

2 целых 3/10 a- 1 целая 2/3a при a=6

Answer 1

(2+3/10)*а - (1+2/3)*а = (2*10+3)а/10 - (1*3+2)а/3 = 23а/10 - 5а/3 = 69а/30 - 50а/30 = 19а/30 = (при а = 6) = 16*6/30 = 16/5 = 3+1/5
3 целых одна пятая.