Question

2sin²x-5sin+2=0

Помогите!

Answer 1

2sin²x-5sin+2=0  z=sinx
2z²-5z+2=0   √D=√25-16=3
z1=1/4[5-3]=1/2
z2=1/4[5+3]=2>1
   
sinx=1/2
x=(-1)ⁿ*π/6+πn   n∈Z