Question

Вычислить интеграл!!!!!!!

Answer 1

$int {(5-3x)^7} , dx =$
[ $u=5-3x; du=-3dx$ ] =
= $- frac{1}{3} int{u^7} , du = -u^8/24 + C =$
= $- frac{1}{24} (5-3x)^8 + C$