Question

решите математику))))

Answer 1

$y=x-sin(x^3)+10\y'=1-cos(x^3)*3x^2\y''=-((cos(x^3))'(3x^2)+(cos(x^3)(3x^2)')\y''=-(-3x^2*sin(x^3)*3x^2)+6x*cos(x^3)\y''=9x^4*sin(x^3)-6x*cos(x^3)$