Question

Решите, пожалуйста!!!

Answer 1

$displaystyle frac{1-log_a^3b}{(log_ab+log_ba+1)log_a frac{a}{b} } = frac{(1-log_ab)(1+log_ab+log_a^2b)}{(1+log_a^2b+log_ab)(log_aa-log_ab)} =\ \ \ = frac{1-log_ab}{1-log_ab}=1.$