Question

$frac{1-cos a^{2}+tg a^{2} *cos a^{2} }{sin a^{2} }$

Answer 1

$frac{1-cos^2alpha+tg^2alpha*cos^2alpha}{sin^2alpha} = frac{sin^2alpha+ frac{sin^2alpha}{cos^2alpha}*cos^2alpha }{sin^2alpha} = frac{sin^2alpha+sin^2alpha}{sin^2alpha} = frac{2sin^2alpha}{sin^2alpha} =2$
Ответ: 2