Question

3х^2+8х-3=0 помогите пж

Answer 1

3x²+8x-3=0;
D = b² - 4ac = 64 - (4 * 3 * (-3)) = 64 + 36 = 100;
x1 = (-b-√D)/2a = (-8-10)/6 = -18/6 = -3;
x2 = (-b+√D)/2a = (-8+10)/6 = 2/6 = 1/3;

Answer 2

$3x^2+8x-3=0 \ D=64+36=100=10^2 \ x_1= frac{-8-10}{6}=-6 \ \ x_2= frac{-8+10}{6}= frac{1}{3}$

Answer 3

лучший

Answer 4

Спс