Question

вычислите производную функции y=(2x^3+3x)lnx для x=1

Answer 1

y'(x) = (6x²+3)lnx+(2x³+3x)/x
y'(1) = (6*1²+3)ln1+(2*1³+3*1)/1 = (6+3)*0+(2+3)/1 = 5