Question

СРОЧНО!Решите уравнение!!!!ДАЮ 20 БАЛЛОВ!!!!!!!!!!!!!!!!!!!!!

Answer 1

$x^{3}+ x^{2} -4x-4=0 \ x^{2} (x+1)-4(x+1)=0 \ (x+1)( x^{2} -4)=0 \ (x+1)(x-2)(x+2)=0 \ x=-1 x= 2 x=-2$

Answer 2

x³+x³-4x-4=0
x²(x+1)-4(x+1)=0
(x²-4)(x+1)=0
(x-2)(x+2)(x+1)=0
x=2, x=-2, x=-1