Question

Решите , пожалуйста

Answer 1

$6 sqrt{3}+sqrt{27}-3sqrt{75}=6 sqrt{3}+sqrt{9 cdot 3}-3sqrt{25cdot3}= \ =6 sqrt{3}+3sqrt{3}-15sqrt{3}=-6 sqrt{3} \\ sqrt{50}-2 sqrt{2} = sqrt{25cdot2}-2 sqrt{2} =5 sqrt{2}-2 sqrt{2} =3 sqrt{2} \\ ( 2- sqrt{3} )^2=2^2-2cdot2cdot sqrt{3}+( sqrt{3} )^2 =4-4 sqrt{3}+3=7-4 sqrt{3}$