Question

решение на все эти задачи только решение и всё

Answer 1

CD = √(10²-6²) = √(100-36) = √64 = 8
AC = √(4²+8²) = √(16+64) = √80 = 4√5
----------
BD = √(5²+5²) = √50 = 5√2
AB = BD = 5√2
AD = √((5√2)²+(5√2)²) = √(50+50) = √100 = 10
P(ABCD) = 5√2 + 5 + 5 + 10 = 20+5√2
----------
BN=CN=12
BC = 2*12 = 24
CK=AK = 9
AC = 9*2 = 18
AB = √(24²+18²) = √(6²*(4²+3²)) = 6√(16+9) = 6√25 = 30
P(ABC) = 24+18+30 = 72
--------
FD = 1/2*(AD-BC) = 1/2*(11-6) = 5/2 
CF = FD = 5/2
CD = √((5/2)²+(5/2)²) = √(50/4) = 5/2*√2 = 5/√2
AB = CD = 5/√2