Question

(2a−b)^2÷ (4a^3−ab^2)/3

Answer 1

(2a-b)²÷(4a³-ab²)/3=
=(2a-b)²/ 4a³-ab²/3=
=(2a-b)²/(4a³-ab²)×3=
=(2a-b)²/a×(4a²-b²)×3=
=(2a-b)²/a×(2a-b)×(2a+b)×3=
=2a-b/a×(2a+b)×3=
=2a-b/3a×(2a+b)=
=2a-b/6a²+3ab.