Question

Найдите производную функций под номером номер 147 (а,б)

Answer 1

f(x) = (x + 5)(x - 4) = x² - 4x + 5x - 20 = x² + x - 20
f'(x) = (x²)' + (x)' - (20)' = 2x + 1

f(x) = √2x² - (3x - 2)(5x + 1) = √2x² - 15x² - 3x + 10x + 2 = (√2 - 15)x² +7x + 2
f'(x) = (√2 - 15)(x²)' + 7(x)' + 2' = 2(√2 - 15)x + 7