Question

4x²-18x+8=0 реши квадратное уравнение x1=? x2=?

Answer 1

$4x^2-18x+8=0 \ D=324-128=196=14^2 \ x_1= frac{18+14}{8}= 4 \ \ x_2= frac{18-14}{8}= frac{1}{2}$

Answer 2

$4x^{2} -18x+8=0 \ D= b^{2}-4ac=18^{2}-4*4*8= 324- 128=196 D textgreater 0 \ x_{1} = frac{-b+ sqrt{D} }{2a} = frac{18+14}{8} = frac{32}{8}=4; \ x_{2} = frac{-b- sqrt{D} }{2a}= frac{18-14}{8}= frac{4}{8}= frac{1}{2}= 0,5$