Question

СРОЧНО!!!!!!.
Решите уравнение

Answer 1

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Answer 2

2√x(x+2)=x+4
{x(x+2)≥0⇒x≤-2 U x≥0
{x+4≥0⇒x≥-4
x∈[-4;-2] U [0;∞)
x(x+2)=(x+4)²
x²+2x=x²+8x+16
8x-2x=-16
6x=-16
x=-8/3