Question

Решите уравнение:
2x^2-3x+5/6x+10 + 1,5x+2,5/2x^2-3x+5 = 1

Answer 1

(2x^2-3x+5)/(6x+10) + (1,5x+2,5)/(2x^2-3x+5 )= 1
(2x^2-3x+5)/(6x+10) + (6x+10)/4(2x^2-3x+5) = 1
6x+10≠0⇒x≠-5/3
(2x^2-3x+5)(/6x+10) =t
t+1/4t=1
4t²-4t+1=0
(2t-1)²=0
2t-1=0
t=1/2
(2x²-3x+5)/(6x+10)=1/2
4x²-6x+10=6x+10
4x²-12x=0
4x(x-3)=0
x=0
x=3