Question

Решите короч:
(16)/(x^(2)-64)-(x)/(x-8)=-1

Answer 1

$frac{16}{ {x}^{2} - 64} - frac{x}{x - 8} = - 1 \ 16 - x(x + 8) = - {x}^{2} + 64 \ 16 - {x}^{2} - 8x + {x}^{2} - 64 = 0 \ 8x = - 48 \ x = frac{ - 48}{8} \ x = - 6$

Answer 2

ааааа, точняк, спасибо)))

Answer 3

$frac{16}{ x^{2} -64} - frac{x}{x-8}=-1\\ frac{16}{(x-8)(x+8)}- frac{x}{x-8}+1=0 \\ frac{16- x^{2} -8x+ x^{2} -64}{(x-8)(x+8) }=0\\ frac{-8x -48}{(x-8)(x+8)} =0$
- 8x - 48 = 0           x ≠ 8        x ≠ - 8
- 8x = 48
x = - 6