Question

3a^2+7a-6=0 решите уравнение

Answer 1

3a²+7x-6=0
D=49+72=121
x1=(-7-11)/6=-3
x2=(-7+11)/6=2/3

Answer 2

$displaystyle 3a^2 + 7a - 6 = 0\ D = b^2 - 4ac = 7^2 - 4cdot 3cdot (-6) = 49 + 72 = 121 = 11^2 \ x_1 = frac{-7+11}{6} = frac{4}{6} = frac{2}{3} \ x_2 = frac{-7-11}{6} = -3$