Question

Помогите! Даю максимумально!
X²-3x-4 и Х-2х²-1

Answer 1

${x}^{2} - 3x - 4 = a(x - x1)(x - x2) = \ =(x - 4)(x + 1) \ {x}^{2} - 3x - 4 = 0 \ d = 9 + 16 = 25 \ x1 = (3 + 5) div 2 = 4 \ x2 = (3 - 5) div 2 = - 1$
$- 2 {x}^{2} + x - 1 = a(x - x1)(x - x2) = \ = - 2 {x}^{2} + x - 1 \ - 2 {x}^{2} + x - 1 = 0 \ d = 1 - 8 < 0$