Question

2㏒₄(x+2)=1+㏒₄(3/4-x)

Answer 1

ОДЗ
{x+2>0⇒x>-2
{3/4-x>0⇒x<3/4
x∈(-2;3/4)
(x+2)²=4(3/4-x)
x²+4x+4-3+4x=0
x²+8x+1=0
D=64-4=60
x1=(-8-2√15)/2=-4-√15∉ОДЗ
x2=-4+√15