Question

Помогите решить 4 и 3

Answer 1

(х+1)³+(х-1)³-2х³=12
х³+3х²+3х+1+х³-3х²+3х-1-2х³=12
6х=13
х=13/6= 2 1/6

(1+у)³+(1-у)³-6у²=3у-1
1+3у+3у²+у³+1-3у+3у²-у³-6у²=3у-1
2=3у-1
3у-1=2
3у=3
у=1