Question

решите:
(а-4/а^2+4а+16)+(12а/а^3-64)-(1/а-4)=

Answer 1

$frac{a-4}{a^{2}+4a+16}+ frac{12a}{(a-4)(a^{2}+4a+16)}- frac{1}{a-4}= frac{(a-4)^{2}+12a-(a^{2}+4a+16)}{(a-4)(a^{2}+4a+16)}=frac{a^{2}-8a+16+12a-a^{2}-4a-16)}{(a-4)(a^{2}+4a+16)}=frac{0}{(a-4)(a^{2}+4a+16)}=0$

Answer 2

__a-4_____  + __12a___  - __1__  =___ (a-4)( a-4) + 12a - (a^2+4a+16)__ =0
 a^2+4a+16        a^3-64        a-4                    a^3-64