Question

раскрыть скобки и решить
a) (12а+5b)+(8a-11b)+(9b-5a)
B) (3x+10y)-(6x+3y)+(6y-8x)
C) (8c^2+3c)+(-7c^2-11c+3)-(-3c^2-4)

Answer 1

12а+5b+8a-11b+9b-5a
12a+8a-5a=-5b+11b-9b
-1a=7b

Answer 2

a) (12а+5b)+(8a-11b)+(9b-5a)=12а+5b+8a-11b+9b-5a=15a+3b
B) (3x+10y)-(6x+3y)+(6y-8x)=3x+10y-6x-3y+6y-8x=13y-11x
C) $(8c^{2}+3c)+(-7c^{2}-11c+3)-(-3c^{2}-4)=8c^{2}+3c-7c^{2}-11c+3+3c^{2}+4=4c^{2}-8c+7$