Question

(3x^2-1) (2x+1)
(5c-1)(c^2-5c+1)
-8(y-1)(y+5(
Помогите пожалуйста

Answer 1

(3x² - 1)(2x + 1) = 6x³ + 3x² - 2x - 1

(5c - 1)(c² - 5c + 1) = 5c³ - 25c² + 5c - c² + 5c - 1 = 5c³ - 26c² + 10c - 1

- 8(y - 1)(y + 5) = - 8(y² + 5y - y - 5) = - 8(y² + 4y - 5) = - 8y² - 32y + 40