Question

Решите систему уравнений.
x+y-6=0
2x^2-y^2=-23

Answer 1

x+y-6=0
2x²-y²= -23

x=6-y
2(6-y)²-y²= -23

x=6-y
2(36-12y+y²)-y²= -23

x=6-y
72-24y+2y²-y²= -23

x=6-y
y²-24y+95=0

D=576-4*95=576-380=196
y=(24+14)/2=19
y=(24-14)/2=5

y=19
x= -13

y=5
x=1

Ответ: (-13:19);(1;5)