Question

решите уравнение :
16x^2 - 4x=0
^ - степень

Answer 1

$4x \times (4x - 1) = 0$
$x \times (4x - 1) = 0$
$x = 0 \\ x = \frac{1}{4}$

$x1 = 0 \\ x2 = \frac{1}{4}$

Answer 2

16x^2 -4x = 0
4x(4x - 1) = 0 
4x =  0  или 4x-1 = 0
x = 0             4x = 1
                         x=1/4

проверка
x = 0:
16 * 0^2 - 4 * 0 = 0    
0 - 0 = 0 ВЕРНО!

x=1/4
16 * (1/4)^2 - 4 * 1/4 = 0
16 * 1/16 - 4/4 = 0
1 - 1 = 0 ВЕРНО!