Question

плиз
$(3x + 4) {}^{2} - 10x - (x - 4)(4 + x)$
при х=-0,1

Answer 1

(3x+4)²-10x-(x-4)(4+x)= 9x²+16+24x-10x-(x²-16)= 9x²+16+14x-x²+16= 8x²+14x+32= 2(4x²+7x+16)=
2(4(-0,1)²+7(-0,1)+16)= 2(4*0,1²-1,7+16)= 2*15,34=
30,68

Answer 2

$(3x+4)^2-10x-(x-4)(x+4)=9x^2+24x+16-x^2-4x+4x+16\\-10x=8x^2+14x+32=8*(-0,1)^2+14(-0,1)+32=\\=8*( \frac{1}{10})^2-\frac{7}{5} +32=\frac{2}{25} -\frac{7}{5}+32=\frac{767}{25} =30,68$