Question

sin6x=cos2x !!!!!помогите!!!!! срочно нужно)

Answer 1

sin6x-sin(π/2-2x)=0
2sin(4x-π/4)cos(2x+π/4)=0
sin(4x-π/4)=0
4x-π/4=πk
4x=π/4+πk
x=π/16+πk/4,k∈z
cos(2x+π/4)=0
2x+π/4=π/2+πk
2x=π/4+πk
x=π/8+πk/2,k∈z